1/x+5=x+45/500

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Solution for 1/x+5=x+45/500 equation:


D( x )

x = 0

x = 0

x = 0

x in (-oo:0) U (0:+oo)

1/x+5 = x+45/500 // - x+45/500

1/x-x-(45/500)+5 = 0

1/x-x-9/100+5 = 0

1*x^-1-1*x^1+491/100*x^0 = 0

(491/100*x^1-1*x^2+1*x^0)/(x^1) = 0 // * x^2

x^1*(491/100*x^1-1*x^2+1*x^0) = 0

x^1

(491/100)*x-x^2+1 = 0

(491/100)*x-x^2+1 = 0

DELTA = (491/100)^2-(-1*1*4)

DELTA = 281081/10000

DELTA > 0

x = ((281081/10000)^(1/2)-(491/100))/(-1*2) or x = (-(491/100)-(281081/10000)^(1/2))/(-1*2)

x = ((281081/10000)^(1/2)-491/100)/(-2) or x = ((281081/10000)^(1/2)+491/100)/2

x in { ((281081/10000)^(1/2)-491/100)/(-2), ((281081/10000)^(1/2)+491/100)/2}

x in { ((281081/10000)^(1/2)-491/100)/(-2), ((281081/10000)^(1/2)+491/100)/2 }

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