1/x+3/(x-7)=0

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Solution for 1/x+3/(x-7)=0 equation: 



1/x+3/(x-7)=0



Domain of the equation: x!=0

x∈R





Domain of the equation: (x-7)!=0

We move all terms containing x to the left, all other terms to the right

x!=7

x∈R



We calculate fractions


(1*(x-7))/(x^2-7x)+3x/(x^2-7x)=0



We calculate terms in parentheses: +(1*(x-7))/(x^2-7x), so:

1*(x-7))/(x^2-7x

We add all the numbers together, and all the variables

-7x+1*(x-7))/(x^2

We multiply all the terms by the denominator


-7x*(x^2+1*(x-7))

Back to the equation:

+(-7x*(x^2+1*(x-7)))



We multiply all the terms by the denominator


((-7x*(x^2+1*(x-7))))*(x^2-7x)+3x=0



We calculate terms in parentheses: +((-7x*(x^2+1*(x-7))))*(x^2-7x), so:

(-7x*(x^2+1*(x-7))))*(x^2-7x

We add all the numbers together, and all the variables

-7x+(-7x*(x^2+1*(x-7))))*(x^2

Back to the equation:

+(-7x+(-7x*(x^2+1*(x-7))))*(x^2)



We add all the numbers together, and all the variables

3x+(-7x+(-7x*(x^2+1*(x-7))))*x^2=0

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