1/x+2/(x+4)=0.5

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Solution for 1/x+2/(x+4)=0.5 equation:


D( x )

x+4 = 0

x = 0

x+4 = 0

x+4 = 0

x+4 = 0 // - 4

x = -4

x = 0

x = 0

x in (-oo:-4) U (-4:0) U (0:+oo)

2/(x+4)+1/x = 0.5 // - 0.5

2/(x+4)+1/x-0.5 = 0

(2*x)/(x*(x+4))+(1*(x+4))/(x*(x+4))+(-0.5*x*(x+4))/(x*(x+4)) = 0

1*(x+4)-0.5*x*(x+4)+2*x = 0

3*x-0.5*x^2-2*x+4 = 0

x-0.5*x^2+4 = 0

x-0.5*x^2+4 = 0

x-0.5*x^2+4 = 0

DELTA = 1^2-(-0.5*4*4)

DELTA = 9

DELTA > 0

x = (9^(1/2)-1)/(-0.5*2) or x = (-9^(1/2)-1)/(-0.5*2)

x = -2 or x = 4

(x+2)*(x-4) = 0

((x+2)*(x-4))/(x*(x+4)) = 0

((x+2)*(x-4))/(x*(x+4)) = 0 // * x*(x+4)

(x+2)*(x-4) = 0

( x+2 )

x+2 = 0 // - 2

x = -2

( x-4 )

x-4 = 0 // + 4

x = 4

x in { -2, 4 }

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