1/x+1/y/x+y

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Solution for 1/x+1/y/x+y equation: 


D( x )

x = 0

x = 0

x = 0

x in (-oo:0) U (0:+oo)

1/x+(1/y)/x+y = 0

x^-1+x^-1*y^-1+y = 0

t_1 = x^-1

1*t_1^1+t_1^1*y^-1+y = 0

t_1*y^-1+y = 0 // - y

t_1*y^-1 = -y // : y^-1

t_1 = -y/(y^-1)

t_1 = -y^2

t_1 = -y^2

x^-1+y^2 = 0

1*x^-1 = -y^2 // : 1

x^-1 = -y^2

-1 < 0

1/(x^1) = -y^2 // * x^1

1 = x^1*(-y^2) // : -y^2

1/(-y^2) = x^1

x = 1/(-y^2)

x = 1/(-y^2)

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