If it's not what You are looking for type in the equation solver your own equation and let us solve it.
1/x+1/x+4=x+5/x+4
We simplify the equation to the form, which is simple to understand
1/x+1/x+4=x+5/x+4
We move all terms containing x to the left and all other terms to the right.
+1x+1x-1x-1x=+4-4
We simplify left and right side of the equation.
0x=0
0=0
This equation is an identity, so all real numbers are solutions.
| 5x^3-42x=27 | | 5(7-2n)= | | x+4-112=x | | x^2-y+7=0 | | 3sin(X)=sin(X)+1 | | 3sinx=sinx+1 | | 8(5n)= | | (7y+3u-4)(6y+5)= | | 8(7-2n)= | | n-(54)=96 | | secx=0 | | y=30+4x | | y=30+4 | | 3x(x-2)-4x(x-1)=-15 | | 2(x+3)=5(x-1-4x) | | (7m^2-3-7)(m^2-7m-6)= | | 6v^4+5v^3-6v^2=0 | | 3x-(4x+9)=6x-37 | | (3x^2)-1.5x-5=0 | | 3(x-2)+11=2(x-5) | | 0=10x^2+29x+18 | | n+(-14)=-35 | | In(10-x)+In(-6-x)=In(-34-15x) | | -4-5=6-3x+4x | | 0=ax^2+bx+c | | 7.3a-9.2=3.94 | | 12cos(x)=7 | | x^2-.666x-3.222=0 | | 3(6x-4)+10=70 | | 7+2x=3x+4 | | x^3+cos(x)=x^2+4 | | 3(y+5)+10(y-4)+5= |