1/x+1/(x+8)=0.9/16

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Solution for 1/x+1/(x+8)=0.9/16 equation: 



1/x+1/(x+8)=0.9/16

We move all terms to the left:

1/x+1/(x+8)-(0.9/16)=0



Domain of the equation: x!=0

x∈R





Domain of the equation: (x+8)!=0

We move all terms containing x to the left, all other terms to the right

x!=-8

x∈R



We add all the numbers together, and all the variables

1/x+1/(x+8)-(+0.9/16)=0

We get rid of parentheses

1/x+1/(x+8)-0.9/16=0

We calculate fractions


(16x+128)/(16x^2+128x)+16x/(16x^2+128x)+(-0.9*x*(x+8))/(16x^2+128x)=0



We calculate terms in parentheses: +(-0.9*x*(x+8))/(16x^2+128x), so:

-0.9*x*(x+8))/(16x^2+128x

We add all the numbers together, and all the variables

128x-0.9*x*(x+8))/(16x^2

We multiply all the terms by the denominator


128x*(16x^2-0.9*x*(x+8))

Back to the equation:

+(128x*(16x^2-0.9*x*(x+8)))



We multiply all the terms by the denominator


(16x+128)+16x+((128x*(16x^2-0.9*x*(x+8))))*(16x^2+128x)=0



We calculate terms in parentheses: +((128x*(16x^2-0.9*x*(x+8))))*(16x^2+128x), so:

(128x*(16x^2-0.9*x*(x+8))))*(16x^2+128x

We add all the numbers together, and all the variables

128x+(128x*(16x^2-0.9*x*(x+8))))*(16x^2

Back to the equation:

+(128x+(128x*(16x^2-0.9*x*(x+8))))*(16x^2)



We add all the numbers together, and all the variables

16x+(16x+128)+(128x+(128x*(16x^2-0.9*x*(x+8))))*16x^2=0

We get rid of parentheses

16x+16x+(128x+(128x*(16x^2-0.9*x*(x+8))))*16x^2+128=0

We add all the numbers together, and all the variables

32x+(128x+(128x*(16x^2-0.9*x*(x+8))))*16x^2+128=0

We move all terms containing x to the left, all other terms to the right

32x+(128x+(128x*(16x^2-0.9*x*(x+8))))*16x^2=-128

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