1/x+1/(x+3)=(x+4)/(x+3)

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Solution for 1/x+1/(x+3)=(x+4)/(x+3) equation:


D( x )

x = 0

x+3 = 0

x = 0

x = 0

x+3 = 0

x+3 = 0

x+3 = 0 // - 3

x = -3

x in (-oo:-3) U (-3:0) U (0:+oo)

1/(x+3)+1/x = (x+4)/(x+3) // - (x+4)/(x+3)

1/(x+3)-((x+4)/(x+3))+1/x = 0

1/(x+3)+(-1*(x+4))/(x+3)+1/x = 0

(1*x)/(x*(x+3))+(-1*x*(x+4))/(x*(x+3))+(1*(x+3))/(x*(x+3)) = 0

1*(x+3)-1*x*(x+4)+1*x = 0

x-x^2-3*x+3 = 0

3-x^2-2*x = 0

3-x^2-2*x = 0

3-x^2-2*x = 0

DELTA = (-2)^2-(-1*3*4)

DELTA = 16

DELTA > 0

x = (16^(1/2)+2)/(-1*2) or x = (2-16^(1/2))/(-1*2)

x = -3 or x = 1

(x+3)*(x-1) = 0

((x+3)*(x-1))/(x*(x+3)) = 0

((x+3)*(x-1))/(x*(x+3)) = 0 // * x*(x+3)

(x+3)*(x-1) = 0

( x+3 )

x+3 = 0 // - 3

x = -3

( x-1 )

x-1 = 0 // + 1

x = 1

x in { -3}

x = 1

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