1/x+1/(x+1)=2

Solution for 1/x+1/(x+1)=2 equation:

1/x+1/(x+1)=2

We move all terms to the left:

1/x+1/(x+1)-(2)=0


Domain of the equation: x!=0

x∈R



Domain of the equation: (x+1)!=0

We move all terms containing x to the left, all other terms to the right

x!=-1

x∈R


We calculate fractions


(1*(x+1))/(x^2+x)+x/(x^2+x)-2=0


We calculate terms in parentheses: +(1*(x+1))/(x^2+x), so:

1*(x+1))/(x^2+x

We add all the numbers together, and all the variables

x+1*(x+1))/(x^2

We multiply all the terms by the denominator


x*(x^2+1*(x+1))

Back to the equation:

+(x*(x^2+1*(x+1)))


We multiply all the terms by the denominator


((x*(x^2+1*(x+1))))*(x^2+x)+x-2*(x^2+x)=0


We calculate terms in parentheses: +((x*(x^2+1*(x+1))))*(x^2+x), so:

(x*(x^2+1*(x+1))))*(x^2+x

We add all the numbers together, and all the variables

x+(x*(x^2+1*(x+1))))*(x^2

Back to the equation:

+(x+(x*(x^2+1*(x+1))))*(x^2)


We add all the numbers together, and all the variables

x+(x+(x*(x^2+1*(x+1))))*x^2-2*(x^2+x)=0

We multiply parentheses

-2x^2+x+(x+(x*(x^2+1*(x+1))))*x^2-2x=0

We add all the numbers together, and all the variables

-2x^2-1x+(x+(x*(x^2+1*(x+1))))*x^2=0