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1/x+1/(2x)=4/(x+2)
We move all terms to the left:
1/x+1/(2x)-(4/(x+2))=0
Domain of the equation: x!=0
x∈R
Domain of the equation: 2x!=0
x!=0/2
x!=0
x∈R
Domain of the equation: (x+2))!=0We calculate fractions
x∈R
We do not support expression: x^3
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