1/x+(-1/2x)=5

Solution for 1/x+(-1/2x)=5 equation:

1/x+(-1/2x)=5

We move all terms to the left:

1/x+(-1/2x)-(5)=0


Domain of the equation: x!=0

x∈R



Domain of the equation: 2x)!=0

x!=0/1

x!=0

x∈R


We get rid of parentheses

1/x-1/2x-5=0

We calculate fractions


2x/2x^2+(-x)/2x^2-5=0

We add all the numbers together, and all the variables

2x/2x^2+(-1x)/2x^2-5=0

We multiply all the terms by the denominator


2x+(-1x)-5*2x^2=0

Wy multiply elements

-10x^2+2x+(-1x)=0

We get rid of parentheses

-10x^2+2x-1x=0

We add all the numbers together, and all the variables

-10x^2+x=0

a = -10; b = 1; c = 0;
Δ = b2-4ac
Δ = 12-4·(-10)·0
Δ = 1
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{1}=1$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(1)-1}{2*-10}=\frac{-2}{-20}
=1/10
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(1)+1}{2*-10}=\frac{0}{-20}
=0
$