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1/w-2-3/5w-10=2/5w-10
We move all terms to the left:
1/w-2-3/5w-10-(2/5w-10)=0
Domain of the equation: w!=0
w∈R
Domain of the equation: 5w!=0
w!=0/5
w!=0
w∈R
Domain of the equation: 5w-10)!=0We add all the numbers together, and all the variables
w∈R
1/w-3/5w-(2/5w-10)-12=0
We get rid of parentheses
1/w-3/5w-2/5w+10-12=0
We calculate fractions
5w/5w^2+(-2w-3)/5w^2+10-12=0
We add all the numbers together, and all the variables
5w/5w^2+(-2w-3)/5w^2-2=0
We multiply all the terms by the denominator
5w+(-2w-3)-2*5w^2=0
Wy multiply elements
-10w^2+5w+(-2w-3)=0
We get rid of parentheses
-10w^2+5w-2w-3=0
We add all the numbers together, and all the variables
-10w^2+3w-3=0
a = -10; b = 3; c = -3;
Δ = b2-4ac
Δ = 32-4·(-10)·(-3)
Δ = -111
Delta is less than zero, so there is no solution for the equation
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