1/w-1-3/4w-4=1/4w-4

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Solution for 1/w-1-3/4w-4=1/4w-4 equation: 



1/w-1-3/4w-4=1/4w-4

We move all terms to the left:

1/w-1-3/4w-4-(1/4w-4)=0



Domain of the equation: w!=0

w∈R





Domain of the equation: 4w!=0

w!=0/4

w!=0

w∈R





Domain of the equation: 4w-4)!=0

w∈R



We add all the numbers together, and all the variables

1/w-3/4w-(1/4w-4)-5=0

We get rid of parentheses

1/w-3/4w-1/4w+4-5=0

We calculate fractions


4w/4w^2+(-1w-3)/4w^2+4-5=0

We add all the numbers together, and all the variables

4w/4w^2+(-1w-3)/4w^2-1=0

We multiply all the terms by the denominator


4w+(-1w-3)-1*4w^2=0

Wy multiply elements

-4w^2+4w+(-1w-3)=0

We get rid of parentheses

-4w^2+4w-1w-3=0

We add all the numbers together, and all the variables

-4w^2+3w-3=0

a = -4; b = 3; c = -3;
Δ = b2-4ac
Δ = 32-4·(-4)·(-3)
Δ = -39
Delta is less than zero, so there is no solution for the equation

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