1/u+2=-3/4u+8+2

Solution for 1/u+2=-3/4u+8+2 equation:

D( u )

u = 0

u = 0

u = 0

u in (-oo:0) U (0:+oo)

1/u+2 = (-3/4)*u+2+8 // - (-3/4)*u+2+8

1/u-((-3/4)*u)-8-2+2 = 0

(3/4)*u+1/u-8-2+2 = 0

3/4*u^1+1*u^-1-8*u^0 = 0

(3/4*u^2-8*u^1+1*u^0)/(u^1) = 0 // * u^2

u^1*(3/4*u^2-8*u^1+1*u^0) = 0

u^1

(3/4)*u^2-8*u+1 = 0

(3/4)*u^2-8*u+1 = 0

DELTA = (-8)^2-(1*4*(3/4))

DELTA = 61

DELTA > 0

u = (61^(1/2)+8)/(2*(3/4)) or u = (8-61^(1/2))/(2*(3/4))

u = 2/3*(61^(1/2)+8) or u = 2/3*(8-61^(1/2))

u in { 2/3*(8-61^(1/2)), 2/3*(61^(1/2)+8)} 

u in { 2/3*(8-61^(1/2)), 2/3*(61^(1/2)+8) }