1/q+1/2q=1/12

Solution for 1/q+1/2q=1/12 equation:

1/q+1/2q=1/12

We move all terms to the left:

1/q+1/2q-(1/12)=0


Domain of the equation: q!=0

q∈R



Domain of the equation: 2q!=0

q!=0/2

q!=0

q∈R


We add all the numbers together, and all the variables

1/q+1/2q-(+1/12)=0

We get rid of parentheses

1/q+1/2q-1/12=0

We calculate fractions


(-4q^2)/24q^2+24q/24q^2+12q/24q^2=0

We multiply all the terms by the denominator


(-4q^2)+24q+12q=0

We add all the numbers together, and all the variables

(-4q^2)+36q=0

We get rid of parentheses

-4q^2+36q=0

a = -4; b = 36; c = 0;
Δ = b2-4ac
Δ = 362-4·(-4)·0
Δ = 1296
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$q_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$q_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{1296}=36$
$q_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(36)-36}{2*-4}=\frac{-72}{-8}
=+9
$
$q_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(36)+36}{2*-4}=\frac{0}{-8}
=0
$