1/cos(5x)

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Solution for 1/cos(5x) equation: 


D( x )

cos(5*x) = 0

cos(5*x) = 0

cos(5*x) = 0

cos(5*x) = 0  <=>  5*x = pi*k_1+pi/2 i k_1 należy do I

t_1 = pi*k_1+pi/2

5*x-t_1 = 0

5*x-t_1 = 0 // + t_1

5*x = t_1 // : 5

x = t_1/5

x = pi*k_1+pi/2/5 i k_1 należy do I

x in {( -oo : +oo ) / < pi*k_1+pi/2/5 : pi*k_1+pi/2/5 >} i k_1 -> {I}

1/cos(5*x) = 0

1/cos(5*x) = 0 // * cos(5*x)

1 = 0

x belongs to the empty set

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