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1/c+1/3c=2/3
We move all terms to the left:
1/c+1/3c-(2/3)=0
Domain of the equation: c!=0
c∈R
Domain of the equation: 3c!=0We add all the numbers together, and all the variables
c!=0/3
c!=0
c∈R
1/c+1/3c-(+2/3)=0
We get rid of parentheses
1/c+1/3c-2/3=0
We calculate fractions
27c/27c^2+c/27c^2+(-2c)/27c^2=0
We multiply all the terms by the denominator
27c+c+(-2c)=0
We add all the numbers together, and all the variables
28c+(-2c)=0
We get rid of parentheses
28c-2c=0
We add all the numbers together, and all the variables
26c=0
c=0/26
c=0
Równanie nie ma rozwiązania
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