1/b-9/10b

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Solution for 1/b-9/10b equation: 


D( b )

b = 0

b = 0

b = 0

b in (-oo:0) U (0:+oo)

1/b-((9/10)*b) = 0

(-9/10)*b+1/b = 0

1*b^-1-9/10*b^1 = 0

(1*b^0-9/10*b^2)/(b^1) = 0 // * b^2

b^1*(1*b^0-9/10*b^2) = 0

b^1

(-9/10)*b^2+1 = 0

(-9/10)*b^2+1 = 0

DELTA = 0^2-(1*4*(-9/10))

DELTA = 18/5

DELTA > 0

b = ((18/5)^(1/2)+0)/(2*(-9/10)) or b = (0-(18/5)^(1/2))/(2*(-9/10))

b = -5/9*(18/5)^(1/2) or b = 5/9*(18/5)^(1/2)

b in { -5/9*(18/5)^(1/2), 5/9*(18/5)^(1/2)} 

b in { -5/9*(18/5)^(1/2), 5/9*(18/5)^(1/2) }

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