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1/9x-(5x-1)=7/(6x-(2x-1))
We move all terms to the left:
1/9x-(5x-1)-(7/(6x-(2x-1)))=0
Domain of the equation: 9x!=0
x!=0/9
x!=0
x∈R
Domain of the equation: (6x-(2x-1)))!=0We get rid of parentheses
x∈R
1/9x-5x-(7/(6x-(2x-1)))+1=0
We calculate fractions
-5x+(1*(6x-(2x-1))))/(9x*(6x-(2x-1))))+(-(7*9x)/(9x*(6x-(2x-1))))+1=0
We can not solve this equation
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