1/9(p+18)+1/3(2p+3)=p+1/3

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Solution for 1/9(p+18)+1/3(2p+3)=p+1/3 equation: 



1/9(p+18)+1/3(2p+3)=p+1/3

We move all terms to the left:

1/9(p+18)+1/3(2p+3)-(p+1/3)=0



Domain of the equation: 9(p+18)!=0

p∈R





Domain of the equation: 3(2p+3)!=0

p∈R



We add all the numbers together, and all the variables

1/9(p+18)+1/3(2p+3)-(+p+1/3)=0

We get rid of parentheses

1/9(p+18)+1/3(2p+3)-p-1/3=0

We calculate fractions


-p+(9p2/(9(p+18)*3(2p+3)*3)+(9pp/(9(p+18)*3(2p+3)*3)+(-9pp/(9(p+18)*3(2p+3)*3)=0



We calculate terms in parentheses: +(9p2/(9(p+18)*3(2p+3)*3)+(9pp/(9(p+18)*3(2p+3)*3)+(-9pp/(9(p+18)*3(2p+3)*3), so:

9p2/(9(p+18)*3(2p+3)*3)+(9pp/(9(p+18)*3(2p+3)*3)+(-9pp/(9(p+18)*3(2p+3)*3

We can not solve this equation

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