1/9(9y+18)-9=-1/9(27y-45)

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Solution for 1/9(9y+18)-9=-1/9(27y-45) equation: 



1/9(9y+18)-9=-1/9(27y-45)

We move all terms to the left:

1/9(9y+18)-9-(-1/9(27y-45))=0



Domain of the equation: 9(9y+18)!=0

y∈R





Domain of the equation: 9(27y-45))!=0

y∈R



We calculate fractions


(9y2/(9(9y+18)*9(27y-45)))+(-(-9y9)/(9(9y+18)*9(27y-45)))-9=0



We calculate terms in parentheses: +(9y2/(9(9y+18)*9(27y-45))), so:

9y2/(9(9y+18)*9(27y-45))

We multiply all the terms by the denominator


9y2

We add all the numbers together, and all the variables

9y^2

Back to the equation:

+(9y^2)





We calculate terms in parentheses: +(-(-9y9)/(9(9y+18)*9(27y-45))), so:

-(-9y9)/(9(9y+18)*9(27y-45))

We add all the numbers together, and all the variables

-(-9y^9)/(9(9y+18)*9(27y-45))

We multiply all the terms by the denominator


-(-9y^9)

We do not support eypression: y^9

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