1/9(9t-6)=1/18(t+6)

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Solution for 1/9(9t-6)=1/18(t+6) equation: 



1/9(9t-6)=1/18(t+6)

We move all terms to the left:

1/9(9t-6)-(1/18(t+6))=0



Domain of the equation: 9(9t-6)!=0

t∈R





Domain of the equation: 18(t+6))!=0

t∈R



We calculate fractions


(18tt/(9(9t-6)*18(t+6)))+(-9t9/(9(9t-6)*18(t+6)))=0



We calculate terms in parentheses: +(18tt/(9(9t-6)*18(t+6))), so:

18tt/(9(9t-6)*18(t+6))

We multiply all the terms by the denominator


18tt

Back to the equation:

+(18tt)





We calculate terms in parentheses: +(-9t9/(9(9t-6)*18(t+6))), so:

-9t9/(9(9t-6)*18(t+6))

We multiply all the terms by the denominator


-9t9

We add all the numbers together, and all the variables

-9t^9

We do not support etpression: t^9

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