1/9(128-20w)=0.4(-6.25w+50)

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Solution for 1/9(128-20w)=0.4(-6.25w+50) equation: 



1/9(128-20w)=0.4(-6.25w+50)

We move all terms to the left:

1/9(128-20w)-(0.4(-6.25w+50))=0



Domain of the equation: 9(128-20w)!=0

w∈R



We add all the numbers together, and all the variables

1/9(-20w+128)-(0.4(-6.25w+50))=0

We multiply all the terms by the denominator


-((0.4(-6.25w+50)))*9(-20w+128)+1=0



We calculate terms in parentheses: -((0.4(-6.25w+50)))*9(-20w+128), so:

(0.4(-6.25w+50)))*9(-20w+128

We add all the numbers together, and all the variables

-20w+(0.4(-6.25w+50)))*9(+128

Back to the equation:

-(-20w+(0.4(-6.25w+50)))*9(+128)



We add all the numbers together, and all the variables

-(-20w+(0.4(-6.25w+50)))*9128+1=0

We move all terms containing w to the left, all other terms to the right

-(-20w+(0.4(-6.25w+50)))*9128=-1

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