1/8x-10=-1/4x-8

Solution for 1/8x-10=-1/4x-8 equation:

1/8x-10=-1/4x-8

We move all terms to the left:

1/8x-10-(-1/4x-8)=0


Domain of the equation: 8x!=0

x!=0/8

x!=0

x∈R



Domain of the equation: 4x-8)!=0

x∈R


We get rid of parentheses

1/8x+1/4x+8-10=0

We calculate fractions


4x/32x^2+8x/32x^2+8-10=0

We add all the numbers together, and all the variables

4x/32x^2+8x/32x^2-2=0

We multiply all the terms by the denominator


4x+8x-2*32x^2=0

We add all the numbers together, and all the variables

12x-2*32x^2=0

Wy multiply elements

-64x^2+12x=0

a = -64; b = 12; c = 0;
Δ = b2-4ac
Δ = 122-4·(-64)·0
Δ = 144
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{144}=12$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(12)-12}{2*-64}=\frac{-24}{-128}
=3/16
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(12)+12}{2*-64}=\frac{0}{-128}
=0
$