1/8x+3=-4-1/6x

Solution for 1/8x+3=-4-1/6x equation:

1/8x+3=-4-1/6x

We move all terms to the left:

1/8x+3-(-4-1/6x)=0


Domain of the equation: 8x!=0

x!=0/8

x!=0

x∈R



Domain of the equation: 6x)!=0

x!=0/1

x!=0

x∈R


We add all the numbers together, and all the variables

1/8x-(-1/6x-4)+3=0

We get rid of parentheses

1/8x+1/6x+4+3=0

We calculate fractions


6x/48x^2+8x/48x^2+4+3=0

We add all the numbers together, and all the variables

6x/48x^2+8x/48x^2+7=0

We multiply all the terms by the denominator


6x+8x+7*48x^2=0

We add all the numbers together, and all the variables

14x+7*48x^2=0

Wy multiply elements

336x^2+14x=0

a = 336; b = 14; c = 0;
Δ = b2-4ac
Δ = 142-4·336·0
Δ = 196
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{196}=14$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(14)-14}{2*336}=\frac{-28}{672}
=-1/24
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(14)+14}{2*336}=\frac{0}{672}
=0
$