1/8x+1/56x=7

Solution for 1/8x+1/56x=7 equation:

1/8x+1/56x=7

We move all terms to the left:

1/8x+1/56x-(7)=0


Domain of the equation: 8x!=0

x!=0/8

x!=0

x∈R



Domain of the equation: 56x!=0

x!=0/56

x!=0

x∈R


We calculate fractions


56x/448x^2+8x/448x^2-7=0

We multiply all the terms by the denominator


56x+8x-7*448x^2=0

We add all the numbers together, and all the variables

64x-7*448x^2=0

Wy multiply elements

-3136x^2+64x=0

a = -3136; b = 64; c = 0;
Δ = b2-4ac
Δ = 642-4·(-3136)·0
Δ = 4096
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{4096}=64$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(64)-64}{2*-3136}=\frac{-128}{-6272}
=1/49
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(64)+64}{2*-3136}=\frac{0}{-6272}
=0
$