1/8x+1/2x=2/5

Solution for 1/8x+1/2x=2/5 equation:

1/8x+1/2x=2/5

We move all terms to the left:

1/8x+1/2x-(2/5)=0


Domain of the equation: 8x!=0

x!=0/8

x!=0

x∈R



Domain of the equation: 2x!=0

x!=0/2

x!=0

x∈R


We add all the numbers together, and all the variables

1/8x+1/2x-(+2/5)=0

We get rid of parentheses

1/8x+1/2x-2/5=0

We calculate fractions


(-64x^2)/400x^2+50x/400x^2+200x/400x^2=0

We multiply all the terms by the denominator


(-64x^2)+50x+200x=0

We add all the numbers together, and all the variables

(-64x^2)+250x=0

We get rid of parentheses

-64x^2+250x=0

a = -64; b = 250; c = 0;
Δ = b2-4ac
Δ = 2502-4·(-64)·0
Δ = 62500
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{62500}=250$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(250)-250}{2*-64}=\frac{-500}{-128}
=3+29/32
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(250)+250}{2*-64}=\frac{0}{-128}
=0
$