1/8t-3/4t-3=4

Solution for 1/8t-3/4t-3=4 equation:

1/8t-3/4t-3=4

We move all terms to the left:

1/8t-3/4t-3-(4)=0


Domain of the equation: 8t!=0

t!=0/8

t!=0

t∈R



Domain of the equation: 4t!=0

t!=0/4

t!=0

t∈R


We add all the numbers together, and all the variables

1/8t-3/4t-7=0

We calculate fractions


4t/32t^2+(-24t)/32t^2-7=0

We multiply all the terms by the denominator


4t+(-24t)-7*32t^2=0

Wy multiply elements

-224t^2+4t+(-24t)=0

We get rid of parentheses

-224t^2+4t-24t=0

We add all the numbers together, and all the variables

-224t^2-20t=0

a = -224; b = -20; c = 0;
Δ = b2-4ac
Δ = -202-4·(-224)·0
Δ = 400
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{400}=20$
$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-20)-20}{2*-224}=\frac{0}{-448}
=0
$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-20)+20}{2*-224}=\frac{40}{-448}
=-5/56
$