1/8(z+5)=3/4(z+2)

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Solution for 1/8(z+5)=3/4(z+2) equation: 



1/8(z+5)=3/4(z+2)

We move all terms to the left:

1/8(z+5)-(3/4(z+2))=0



Domain of the equation: 8(z+5)!=0

z∈R





Domain of the equation: 4(z+2))!=0

z∈R



We calculate fractions


(4zz/(8(z+5)*4(z+2)))+(-24zz/(8(z+5)*4(z+2)))=0



We calculate terms in parentheses: +(4zz/(8(z+5)*4(z+2))), so:

4zz/(8(z+5)*4(z+2))

We multiply all the terms by the denominator


4zz

Back to the equation:

+(4zz)





We calculate terms in parentheses: +(-24zz/(8(z+5)*4(z+2))), so:

-24zz/(8(z+5)*4(z+2))

We multiply all the terms by the denominator


-24zz

Back to the equation:

+(-24zz)



We get rid of parentheses

4zz-24zz=0

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