1/8(5y-64)=1/5(20+2y)

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Solution for 1/8(5y-64)=1/5(20+2y) equation: 



1/8(5y-64)=1/5(20+2y)

We move all terms to the left:

1/8(5y-64)-(1/5(20+2y))=0



Domain of the equation: 8(5y-64)!=0

y∈R





Domain of the equation: 5(20+2y))!=0

y∈R



We add all the numbers together, and all the variables

1/8(5y-64)-(1/5(2y+20))=0

We calculate fractions


(5y2/(8(5y-64)*5(2y+20)))+(-8y5/(8(5y-64)*5(2y+20)))=0



We calculate terms in parentheses: +(5y2/(8(5y-64)*5(2y+20))), so:

5y2/(8(5y-64)*5(2y+20))

We multiply all the terms by the denominator


5y2

We add all the numbers together, and all the variables

5y^2

Back to the equation:

+(5y^2)





We calculate terms in parentheses: +(-8y5/(8(5y-64)*5(2y+20))), so:

-8y5/(8(5y-64)*5(2y+20))

We multiply all the terms by the denominator


-8y5

We add all the numbers together, and all the variables

-8y^5

We do not support eypression: y^5

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