1/8(5y+64)=1/4(20-12y)

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Solution for 1/8(5y+64)=1/4(20-12y) equation: 



1/8(5y+64)=1/4(20-12y)

We move all terms to the left:

1/8(5y+64)-(1/4(20-12y))=0



Domain of the equation: 8(5y+64)!=0

y∈R





Domain of the equation: 4(20-12y))!=0

y∈R



We add all the numbers together, and all the variables

1/8(5y+64)-(1/4(-12y+20))=0

We calculate fractions


(4y(-)/(8(5y+64)*4(-12y+20)))+(-8y5/(8(5y+64)*4(-12y+20)))=0



We calculate terms in parentheses: +(4y(-)/(8(5y+64)*4(-12y+20))), so:

4y(-)/(8(5y+64)*4(-12y+20))

We add all the numbers together, and all the variables

4y0/(8(5y+64)*4(-12y+20))

We multiply all the terms by the denominator


4y0

We add all the numbers together, and all the variables

4y

Back to the equation:

+(4y)





We calculate terms in parentheses: +(-8y5/(8(5y+64)*4(-12y+20))), so:

-8y5/(8(5y+64)*4(-12y+20))

We multiply all the terms by the denominator


-8y5

We add all the numbers together, and all the variables

-8y^5

We do not support eypression: y^5

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