1/8(5x+7x)15=1/4(x-24)

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Solution for 1/8(5x+7x)15=1/4(x-24) equation: 



1/8(5x+7x)15=1/4(x-24)

We move all terms to the left:

1/8(5x+7x)15-(1/4(x-24))=0



Domain of the equation: 8(5x+7x)15!=0

x∈R





Domain of the equation: 4(x-24))!=0

x∈R



We add all the numbers together, and all the variables

1/8(+12x)15-(1/4(x-24))=0

We calculate fractions


(4xx/(8(+12x)15*4(x-24)))+(-(1*8(+12x)15)/(8(+12x)15*4(x-24)))=0



We calculate terms in parentheses: +(4xx/(8(+12x)15*4(x-24))), so:

4xx/(8(+12x)15*4(x-24))

We multiply all the terms by the denominator


4xx

Back to the equation:

+(4xx)





We calculate terms in parentheses: +(-(1*8(+12x)15)/(8(+12x)15*4(x-24))), so:

-(1*8(+12x)15)/(8(+12x)15*4(x-24))

We multiply all the terms by the denominator


-(1*8(+12x)15)



We calculate terms in parentheses: -(1*8(+12x)15), so:

1*8(+12x)15

Wy multiply elements

8x(+

Back to the equation:

-(8x(+)



We add all the numbers together, and all the variables

-(8x0

Back to the equation:

+(-(8x0)

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