1/8(40x+16=9x-7(2x-1)-5

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Solution for 1/8(40x+16=9x-7(2x-1)-5 equation:



1/8(40x+16=9x-7(2x-1)-5
We move all terms to the left:
1/8(40x+16-(9x-7(2x-1)-5)=0
Domain of the equation: 8(40x+16-(9x-7(2x-1)-5)!=0
x∈R
We multiply all the terms by the denominator
1!=0
There is no solution for this equation

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