1/8(3y-2)=1/4(y+5)

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Solution for 1/8(3y-2)=1/4(y+5) equation: 



1/8(3y-2)=1/4(y+5)

We move all terms to the left:

1/8(3y-2)-(1/4(y+5))=0



Domain of the equation: 8(3y-2)!=0

y∈R





Domain of the equation: 4(y+5))!=0

y∈R



We calculate fractions


(4yy/(8(3y-2)*4(y+5)))+(-8y3/(8(3y-2)*4(y+5)))=0



We calculate terms in parentheses: +(4yy/(8(3y-2)*4(y+5))), so:

4yy/(8(3y-2)*4(y+5))

We multiply all the terms by the denominator


4yy

Back to the equation:

+(4yy)





We calculate terms in parentheses: +(-8y3/(8(3y-2)*4(y+5))), so:

-8y3/(8(3y-2)*4(y+5))

We multiply all the terms by the denominator


-8y3

We add all the numbers together, and all the variables

-8y^3

We do not support eypression: y^3

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