1/8(3d-12)=1/4(d+6)

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Solution for 1/8(3d-12)=1/4(d+6) equation: 



1/8(3d-12)=1/4(d+6)

We move all terms to the left:

1/8(3d-12)-(1/4(d+6))=0



Domain of the equation: 8(3d-12)!=0

d∈R





Domain of the equation: 4(d+6))!=0

d∈R



We calculate fractions


(4dd/(8(3d-12)*4(d+6)))+(-8d3/(8(3d-12)*4(d+6)))=0



We calculate terms in parentheses: +(4dd/(8(3d-12)*4(d+6))), so:

4dd/(8(3d-12)*4(d+6))

We multiply all the terms by the denominator


4dd

Back to the equation:

+(4dd)





We calculate terms in parentheses: +(-8d3/(8(3d-12)*4(d+6))), so:

-8d3/(8(3d-12)*4(d+6))

We multiply all the terms by the denominator


-8d3

We add all the numbers together, and all the variables

-8d^3

We do not support edpression: d^3

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