1/8(10b-2)=5/4b-1/2

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Solution for 1/8(10b-2)=5/4b-1/2 equation: 


b in (-oo:+oo)

(1/8)*(10*b-2) = (5/4)*b-(1/2) // - (5/4)*b-(1/2)

(1/8)*(10*b-2)-((5/4)*b)+1/2 = 0

(1/8)*(10*b-2)+(-5/4)*b+1/2 = 0

1/8*(10*b-2)+(-5*b)/4+1/2 = 0

(1/8*2*4*(10*b-2))/(2*4)+(-5*2*b)/(2*4)+(1*4)/(2*4) = 0

1/8*2*4*(10*b-2)-5*2*b+1*4 = 0

4-2 = 0

2 = 0

2/(2*4) = 0

2/(2*4) = 0 // * 2*4

2 = 0

b belongs to the empty set

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