1/7x+3/4=9/8x=

Solution for 1/7x+3/4=9/8x= equation:

1/7x+3/4=9/8x=

We move all terms to the left:

1/7x+3/4-(9/8x)=0


Domain of the equation: 7x!=0

x!=0/7

x!=0

x∈R



Domain of the equation: 8x)!=0

x!=0/1

x!=0

x∈R


We add all the numbers together, and all the variables

1/7x-(+9/8x)+3/4=0

We get rid of parentheses

1/7x-9/8x+3/4=0

We calculate fractions


1344x^2/896x^2+128x/896x^2+(-1008x)/896x^2=0

We multiply all the terms by the denominator


1344x^2+128x+(-1008x)=0

We get rid of parentheses

1344x^2+128x-1008x=0

We add all the numbers together, and all the variables

1344x^2-880x=0

a = 1344; b = -880; c = 0;
Δ = b2-4ac
Δ = -8802-4·1344·0
Δ = 774400
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{774400}=880$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-880)-880}{2*1344}=\frac{0}{2688}
=0
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-880)+880}{2*1344}=\frac{1760}{2688}
=55/84
$