1/7w-1/5=1/35w,w=35

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Solution for 1/7w-1/5=1/35w,w=35 equation: 



1/7w-1/5=1/35w.w=35

We move all terms to the left:

1/7w-1/5-(1/35w.w)=0



Domain of the equation: 7w!=0

w!=0/7

w!=0

w∈R





Domain of the equation: 35w.w)!=0

w!=0/1

w!=0

w∈R



We add all the numbers together, and all the variables

1/7w-(+1/35w.w)-1/5=0

We get rid of parentheses

1/7w-1/35w.w-1/5=0

We calculate fractions


(-735w^2)/1225w^2+175w/1225w^2+(-175w)/1225w^2=0

We multiply all the terms by the denominator


(-735w^2)+175w+(-175w)=0

We get rid of parentheses

-735w^2+175w-175w=0

We add all the numbers together, and all the variables

-735w^2=0

a = -735; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·(-735)·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$w=\frac{-b}{2a}=\frac{0}{-1470}=0$

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