1/7k-3=2

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Solution for 1/7k-3=2 equation: 



1/7k-3=2

We move all terms to the left:

1/7k-3-(2)=0



Domain of the equation: 7k!=0

k!=0/7

k!=0

k∈R



We add all the numbers together, and all the variables

1/7k-5=0

We multiply all the terms by the denominator


-5*7k+1=0

Wy multiply elements

-35k+1=0

We move all terms containing k to the left, all other terms to the right

-35k=-1

k=-1/-35

k=1/35

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