1/7(x+4)=3x-4(3-x)-8

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Solution for 1/7(x+4)=3x-4(3-x)-8 equation: 


x in (-oo:+oo)

(1/7)*(x+4) = 3*x-(4*(3-x))-8 // - 3*x-(4*(3-x))-8

(1/7)*(x+4)+4*(3-x)-(3*x)+8 = 0

(1/7)*(x+4)+4*(3-x)-3*x+8 = 0

1/7*(x+4)+4*(3-x)-3*x+8 = 0

1/7*(x+4)+4*(3-x)-3*x+8 = 0

8-27/7*x-3*x+88/7 = 0

8-48/7*x+88/7 = 0

144/7-48/7*x = 0

144/7-48/7*x = 0

144/7-48/7*x = 0 // - 144/7

-48/7*x = -144/7 // : -48/7

x = -144/7/(-48/7)

x = 3

x = 3

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