1/7(x+3)=2x-3(4-x)-7

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Solution for 1/7(x+3)=2x-3(4-x)-7 equation: 


x in (-oo:+oo)

(1/7)*(x+3) = 2*x-(3*(4-x))-7 // - 2*x-(3*(4-x))-7

(1/7)*(x+3)+3*(4-x)-(2*x)+7 = 0

(1/7)*(x+3)+3*(4-x)-2*x+7 = 0

1/7*(x+3)+3*(4-x)-2*x+7 = 0

1/7*(x+3)+3*(4-x)-2*x+7 = 0

7-20/7*x-2*x+87/7 = 0

7-34/7*x+87/7 = 0

136/7-34/7*x = 0

136/7-34/7*x = 0

136/7-34/7*x = 0 // - 136/7

-34/7*x = -136/7 // : -34/7

x = -136/7/(-34/7)

x = 4

x = 4

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