1/7(8t-4)=t+14/14

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Solution for 1/7(8t-4)=t+14/14 equation: 



1/7(8t-4)=t+14/14

We move all terms to the left:

1/7(8t-4)-(t+14/14)=0



Domain of the equation: 7(8t-4)!=0

t∈R



We add all the numbers together, and all the variables

1/7(8t-4)-(t+1)=0

We get rid of parentheses

1/7(8t-4)-t-1=0

We multiply all the terms by the denominator


-t*7(8t-4)-1*7(8t-4)+1=0

Wy multiply elements

-7t^2(8-7t(8+1=0

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