1/7(7y+14)-7=-1/2(4y-8)

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Solution for 1/7(7y+14)-7=-1/2(4y-8) equation: 



1/7(7y+14)-7=-1/2(4y-8)

We move all terms to the left:

1/7(7y+14)-7-(-1/2(4y-8))=0



Domain of the equation: 7(7y+14)!=0

y∈R





Domain of the equation: 2(4y-8))!=0

y∈R



We calculate fractions


(2y4/(7(7y+14)*2(4y-8)))+(-(-7y7)/(7(7y+14)*2(4y-8)))-7=0



We calculate terms in parentheses: +(2y4/(7(7y+14)*2(4y-8))), so:

2y4/(7(7y+14)*2(4y-8))

We multiply all the terms by the denominator


2y4

We add all the numbers together, and all the variables

2y^4

We do not support eypression: y^4

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