1/7(7x-3)=-3/2-5/2

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Solution for 1/7(7x-3)=-3/2-5/2 equation: 


x in (-oo:+oo)

(1/7)*(7*x-3) = -3/2-(5/2) // + -3/2-(5/2)

(1/7)*(7*x-3)-(-3/2)+5/2 = 0

(1/7)*(7*x-3)+3/2+5/2 = 0

1/7*(7*x-3)+3/2+5/2 = 0

(1/7*2*(7*x-3))/2+3/2+5/2 = 0

1/7*2*(7*x-3)+3+5 = 0

2*x+15/7+5 = 0

2*x+50/7 = 0

(2*x+50/7)/2 = 0

(2*x+50/7)/2 = 0 // * 2

2*x+50/7 = 0

2*x+50/7 = 0 // - 50/7

2*x = -50/7 // : 2

x = -50/7/2

x = -25/7

x = -25/7

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