1/7(4t-7)=t+7/14

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Solution for 1/7(4t-7)=t+7/14 equation: 


t in (-oo:+oo)

(1/7)*(4*t-7) = t+7/14 // - t+7/14

(1/7)*(4*t-7)-t-(7/14) = 0

(1/7)*(4*t-7)-t-1/2 = 0

1/7*(4*t-7)-t-1/2 = 0

(1/7*2*(4*t-7))/2+(2*(-t))/2-1/2 = 0

1/7*2*(4*t-7)+2*(-t)-1 = 0

-6/7*t-2-1 = 0

-6/7*t-3 = 0

(-6/7*t-3)/2 = 0

(-6/7*t-3)/2 = 0 // * 2

-6/7*t-3 = 0

-6/7*t-3 = 0 // + 3

-6/7*t = 3 // : -6/7

t = 3/(-6/7)

t = -7/2

t = -7/2

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