1/7(4r+28)=2(r+2)

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Solution for 1/7(4r+28)=2(r+2) equation: 



1/7(4r+28)=2(r+2)

We move all terms to the left:

1/7(4r+28)-(2(r+2))=0



Domain of the equation: 7(4r+28)!=0

r∈R



We multiply all the terms by the denominator


-((2(r+2)))*7(4r+28)+1=0



We calculate terms in parentheses: -((2(r+2)))*7(4r+28), so:

(2(r+2)))*7(4r+28





We calculate terms in parentheses: -((2(r+2)))*7(4r+28), so:

(2(r+2)))*7(4r+28





We calculate terms in parentheses: -((2(r+2)))*7(4r+28), so:

(2(r+2)))*7(4r+28





We calculate terms in parentheses: -((2(r+2)))*7(4r+28), so:

(2(r+2)))*7(4r+28





We calculate terms in parentheses: -((2(r+2)))*7(4r+28), so:

(2(r+2)))*7(4r+28





We calculate terms in parentheses: -((2(r+2)))*7(4r+28), so:

(2(r+2)))*7(4r+28





We calculate terms in parentheses: -((2(r+2)))*7(4r+28), so:

(2(r+2)))*7(4r+28





We calculate terms in parentheses: -((2(r+2)))*7(4r+28), so:

(2(r+2)))*7(4r+28





We calculate terms in parentheses: -((2(r+2)))*7(4r+28), so:

(2(r+2)))*7(4r+28





We calculate terms in parentheses: -((2(r+2)))*7(4r+28), so:

(2(r+2)))*7(4r+28





We calculate terms in parentheses: -((2(r+2)))*7(4r+28), so:

(2(r+2)))*7(4r+28





We calculate terms in parentheses: -((2(r+2)))*7(4r+28), so:

(2(r+2)))*7(4r+28





We calculate terms in parentheses: -((2(r+2)))*7(4r+28), so:

(2(r+2)))*7(4r+28





We calculate terms in parentheses: -((2(r+2)))*7(4r+28), so:

(2(r+2)))*7(4r+28





We calculate terms in parentheses: -((2(r+2)))*7(4r+28), so:

(2(r+2)))*7(4r+28





We calculate terms in parentheses: -((2(r+2)))*7(4r+28), so:

(2(r+2)))*7(4r+28





We calculate terms in parentheses: -((2(r+2)))*7(4r+28), so:

(2(r+2)))*7(4r+28





We calculate terms in parentheses: -((2(r+2)))*7(4r+28), so:

(2(r+2)))*7(4r+28





We calculate terms in parentheses: -((2(r+2)))*7(4r+28), so:

(2(r+2)))*7(4r+28





We calculate terms in parentheses: -((2(r+2)))*7(4r+28), so:

(2(r+2)))*7(4r+28





We calculate terms in parentheses: -((2(r+2)))*7(4r+28), so:

(2(r+2)))*7(4r+28





We calculate terms in parentheses: -((2(r+2)))*7(4r+28), so:

(2(r+2)))*7(4r+28





We calculate terms in parentheses: -((2(r+2)))*7(4r+28), so:

(2(r+2)))*7(4r+28





We calculate terms in parentheses: -((2(r+2)))*7(4r+28), so:

(2(r+2)))*7(4r+28





We calculate terms in parentheses: -((2(r+2)))*7(4r+28), so:

(2(r+2)))*7(4r+28





We calculate terms in parentheses: -((2(r+2)))*7(4r+28), so:

(2(r+2)))*7(4r+28





We calculate terms in parentheses: -((2(r+2)))*7(4r+28), so:

(2(r+2)))*7(4r+28





We calculate terms in parentheses: -((2(r+2)))*7(4r+28), so:

(2(r+2)))*7(4r+28





We calculate terms in parentheses: -((2(r+2)))*7(4r+28), so:

(2(r+2)))*7(4r+28





We calculate terms in parentheses: -((2(r+2)))*7(4r+28), so:

(2(r+2)))*7(4r+28





We calculate terms in parentheses: -((2(r+2)))*7(4r+28), so:

(2(r+2)))*7(4r+28





We calculate terms in parentheses: -((2(r+2)))*7(4r+28), so:

(2(r+2)))*7(4r+28





We calculate terms in parentheses: -((2(r+2)))*7(4r+28), so:

(2(r+2)))*7(4r+28





We calculate terms in parentheses: -((2(r+2)))*7(4r+28), so:

(2(r+2)))*7(4r+28





We calculate terms in parentheses: -((2(r+2)))*7(4r+28), so:

(2(r+2)))*7(4r+28





We calculate terms in parentheses: -((2(r+2)))*7(4r+28), so:

(2(r+2)))*7(4r+28





We calculate terms in parentheses: -((2(r+2)))*7(4r+28), so:

(2(r+2)))*7(4r+28





We calculate terms in parentheses: -((2(r+2)))*7(4r+28), so:

(2(r+2)))*7(4r+28





We calculate terms in parentheses: -((2(r+2)))*7(4r+28), so:

(2(r+2)))*7(4r+28





We calculate terms in parentheses: -((2(r+2)))*7(4r+28), so:

(2(r+2)))*7(4r+28





We calculate terms in parentheses: -((2(r+2)))*7(4r+28), so:

(2(r+2)))*7(4r+28





We calculate terms in parentheses: -((2(r+2)))*7(4r+28), so:

(2(r+2)))*7(4r+28





We calculate terms in parentheses: -((2(r+2)))*7(4r+28), so:

(2(r+2)))*7(4r+28





							

									
									
									
									
									
									

														
			

			
				

						
				
				
					
			
						
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