1/7(4b-3+11)=2b

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Solution for 1/7(4b-3+11)=2b equation:



1/7(4b-3+11)=2b
We move all terms to the left:
1/7(4b-3+11)-(2b)=0
Domain of the equation: 7(4b-3+11)!=0
b∈R
We add all the numbers together, and all the variables
1/7(4b+8)-2b=0
We add all the numbers together, and all the variables
-2b+1/7(4b+8)=0
We multiply all the terms by the denominator
-2b*7(4b+8)+1=0
Wy multiply elements
-14b^2(4+1=0

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