1/7(3y+7)-5/8=3/4y

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Solution for 1/7(3y+7)-5/8=3/4y equation: 



1/7(3y+7)-5/8=3/4y

We move all terms to the left:

1/7(3y+7)-5/8-(3/4y)=0



Domain of the equation: 7(3y+7)!=0

y∈R





Domain of the equation: 4y)!=0

y!=0/1

y!=0

y∈R



We add all the numbers together, and all the variables

1/7(3y+7)-(+3/4y)-5/8=0

We get rid of parentheses

1/7(3y+7)-3/4y-5/8=0

We calculate fractions


(-168y3/(7(3y+7)*4y*8)+(-140y^23/(7(3y+7)*4y*8)+256y/(7(3y+7)*4y*8)=0



We calculate terms in parentheses: +(-168y3/(7(3y+7)*4y*8)+(-140y^23/(7(3y+7)*4y*8)+256y/(7(3y+7)*4y*8), so:

-168y3/(7(3y+7)*4y*8)+(-140y^23/(7(3y+7)*4y*8)+256y/(7(3y+7)*4y*8

We do not support eypression: y^23

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