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1/7(2x-5)=2/7x+1
We move all terms to the left:
1/7(2x-5)-(2/7x+1)=0
Domain of the equation: 7(2x-5)!=0
x∈R
Domain of the equation: 7x+1)!=0We get rid of parentheses
x∈R
1/7(2x-5)-2/7x-1=0
We calculate fractions
7x/(98x^2-245x)+(-14x2/(98x^2-245x)-1=0
We calculate fractions
We do not support expression: x^3
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