1/7(14-7p)-2=-2(.5p+3)+6

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Solution for 1/7(14-7p)-2=-2(.5p+3)+6 equation: 



1/7(14-7p)-2=-2(.5p+3)+6

We move all terms to the left:

1/7(14-7p)-2-(-2(.5p+3)+6)=0



Domain of the equation: 7(14-7p)!=0

p∈R



We add all the numbers together, and all the variables

1/7(-7p+14)-(-2(.5p+3)+6)-2=0

We multiply all the terms by the denominator


-((-2(.5p+3)+6))*7(-7p+14)-2*7(-7p+14)+1=0



We calculate terms in parentheses: -((-2(.5p+3)+6))*7(-7p+14), so:

(-2(.5p+3)+6))*7(-7p+14

We add all the numbers together, and all the variables

-7p+(-2(.5p+3)+6))*7(+14

Back to the equation:

-(-7p+(-2(.5p+3)+6))*7(+14)



We add all the numbers together, and all the variables

-(-7p+(-2(.5p+3)+6))*714-2*7(-7p+14)+1=0

Wy multiply elements

-(-7p+(-2(.5p+3)+6))*714-14p(-+1=0

We use the square of the difference formula

-(-7p+(-2(.5p+3)+6))*714-14p(-1=0

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