1/6z-3+5=10

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Solution for 1/6z-3+5=10 equation: 



1/6z-3+5=10

We move all terms to the left:

1/6z-3+5-(10)=0



Domain of the equation: 6z!=0

z!=0/6

z!=0

z∈R



We add all the numbers together, and all the variables

1/6z-8=0

We multiply all the terms by the denominator


-8*6z+1=0

Wy multiply elements

-48z+1=0

We move all terms containing z to the left, all other terms to the right

-48z=-1

z=-1/-48

z=1/48

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